Consider ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.Can it be concluded that ΔWXY ≅ ΔBCD by SAS? Why or why not?

For SAS, the congruent angle must be between the two congruent sides in each triangle. The sides WX and WY meet at W, while BC and BD meet at B, so the included angles would be ∠W and ∠B. The given angles are ∠X and ∠C, which are not included between the listed sides; therefore, SAS does not establish congruence.

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