Solve: sine of open paren 11 pi over 2 plus x close paren is equal to negative 1 half for left bracket pi comma 2 pi right bracket

Since 11π/2 is equivalent to 3π/2 modulo 2π, the equation becomes sin(x + 3π/2) = −1/2. Using sin(x + 3π/2) = −cos x gives cos x = 1/2. In the interval [π, 2π], this occurs at x = 5π/3, so the correct choice is 5π/3.

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