Winston invests $6,000 at an annual rate of 3.2% compounded semiannually. What will be the value of the investment after 1.6 years? A=P⁢(1+(r)/(n))^n⁢t

Use the compound-interest formula with P = 6,000, r = 0.032, n = 2, and t = 1.6. This gives 6,000(1 + 0.032/2)^(2 × 1.6) = 6,000(1.016)^3.2 ≈ $6,312.64. The investment’s value is $6,312.64, choice B.

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