Question 385 • (OC27) MATH COLL ALGEBRA-1200710-S1-Degele-VOL7006P
There are 3 + 4 + 5 = 12 electives, so the total number of ways to choose 2 is 12 × 11 ÷ 2 = 66. To choose one computer elective and one art elective, there are 5 × 3 = 15 possible pairs. Thus, the probability is 15 ÷ 66 ≈ 0.22727, which is choice C, 0.22727.
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