Question 15 • *CR CCSS Math 2 S2 [M2960OX]
Because JL is a diameter, the circle’s radius is half the length of JL. In an equilateral triangle, K lies a distance of √3/2 times JL from the midpoint of JL, which is greater than the circle’s radius, so K is outside the circle. Thus JK and KL each have one endpoint on the circle and one outside; neither is a chord, and neither is tangent because each meets the circle at an endpoint while passing into the circle’s interior.
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