Question 7 • (AG Q3) Math 8: 25-26 (JTurner)
Let x be the number of 4-point problems and y the number of 3-point problems. Since there are 40 problems, x + y = 40; the total score is 4x + 3y = 130. If all 40 problems were worth 3 points, they would total 120 points, so the extra 10 points mean 10 problems were worth 4 points. That leaves 30 problems worth 3 points, matching choice B.
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