Answers 4413VA ALGEBRA 3 SEM ASolving Compound Inequalities

Solving Compound Inequalities — Unit test Answers

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Which compound inequality has no solution?

x + 5 1

3(x + 4) 10

10 < 3(x – 2) + 1 or < 2

11 ≤ 5(x + 3) – 9 and 5(x + 3) – 9 < 21

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Which values are solutions to >–2? Select two options.k = –10k = –7k = –5k = –1k = 0

k = –10

k = –7

k = –5

k = –1

k = 0

Solve the inequality.2(4+2x)≥5x+5

x≤−2

x≥−2

x≤3

x≥3

The inequality x < 9 or x ≥ 14 can be used to represent the hourly wage, x, of each employee at a store. Which are possible values for x? Select two options.$8$9$11$13$14

$11

$13

$14

Which compound inequality could be represented by the graph?

–4 ≤ x ≤ 4

–2 ≤ x ≤ –1

x ≤ –1 or x ≥ 0

x ≤ 3 or x ≥ –1

Which graph represents the solution to the compound inequality?–2x + 4 ≤ 8 and –2x + 4 > –6

A number line with a point at negative 2 with a bold line pointing to the right ending at the open circle at 5.

A number line with an open circle at negative 2 with a bold line pointing to the right ending at the point at negative 5.

A number line with a point at negative 2 with a bold line pointing to the left. An open circle at 5 with a bold line pointing to the right.

A number line with an open circle at negative 2 with a bold line pointing to the left. A point at 5 with a bold line pointing to the right.

The solution to an inequality is represented by the number line. How can this same solution be written using set-builder notation? {x | x > }

Answer not available

What is the solution to –4(8 – 3x) ≥ 6x – 8?

x ≥ –

x ≤ –

x ≥ 4

x ≤ 4

Which graph represents the solution to the compound inequality?4x + 8 < –16 or 4x + 8 ≥ 4

A number line with an open circle at negative 6 with a bold line pointing to the right ending at the point at negative 1.

A number line with a point at negative 6 with a bold line pointing to the right ending at the open circle at negative 1.

A number line with an open circle at negative 6 with a bold line pointing to the left. A point at negative 1 with a bold line pointing to the right.

A number line with a point at negative 6 with a bold line pointing to the left. An open circle at negative 1 with a bold line pointing to the right.

Solve.s – 6 < 24

{s | s < 6}

{s | s < 10}

{s | s < 54}

{s | s < 90}

A hot air balloon can hold up to 300 pounds of weight. The balloon's pilot weighs 140 pounds. How many 20-pound bags of sand (b) can also be carried by the hot air balloon? Select three options.–205810

–2

Which compound inequality is represented by the graph?

x < –4 or x ≥ 3

x < –4 and x ≥ 3

x ≤ –4 or x < 3

x ≤ –4 and x < 3

To fit in an existing frame, the length, x, of a piece of glass must be longer than 12 cm but not longer than 12.2 cm. Which inequality can be used to represent the lengths of the glass that will fit in the frame?

12 < x ≤ 12.2

12 > x ≤ 12.2

x > 12 or x ≤ 12.2

x < 12 or x ≤ 12.2

Three sisters combine their money to purchase a gift for their grandmother. They currently have a total of $26. The gift costs between $30 and $35. The gift cost can be represented by the compound inequality below.30 < 26 + x< 35What is one value for x, the amount of money still needed to buy the gift?

What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12?

(–∞, –3]

[–3, ∞)

(–∞, 15]

[15, ∞)

What value of x is in the solution set of the inequality –2(3x + 2) > –8x + 6?

–6

–5

Which number line represents the solution set for the inequality 3x < –9?

A number line from negative 4 to 4 in increments of 1. A point is at negative 3 and a bold line starts at negative 3 and is pointing to the left.

A number line from negative 4 to 4 in increments of 1. A point is at negative 3 and a bold line starts at negative 3 and is pointing to the right.

A number line from negative 4 to 4 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the left.

A number line from negative 4 to 4 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the right.

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Solving Compound Inequalities — Unit test Answers

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