Miguel stated that any monomial can be a cube root. Sylvia disagreed and said that a monomial cube root must have exponents divisible by 3. Who is correct, and why?

Miguel is correct: a monomial can be the cube root of its own cube. For example, cubing 2x²y gives 8x⁶y³, whose variable exponents are divisible by 3. The exponents in the cube are multiplied by 3; the exponents in the cube root do not need to be divisible by 3. So the choice saying any monomial can be a perfect cube root is correct.

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