What is the y-value in the solution to this system of linear equations?4x + 5y = −12-2x + 3y = −16

Multiply the second equation, −2x + 3y = −16, by 2 to get −4x + 6y = −32. Add it to 4x + 5y = −12; the x terms cancel, leaving 11y = −44. Dividing by 11 gives y = −4, so the correct choice is −4.

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