Answers230CR GeometryArea and Perimeter of Triangles

Area and Perimeter of Triangles — Unit test Answers

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Heron’s formula: Area =

Question illustration
A
square units
Option A
B
square units
Option B
C
square units
Option C
D
square units
Option D
4

Law of sines:

Question illustration
A
StartFraction sine (51 degrees) Over 2.6 EndFraction = StartFraction sine (76 degrees) Over z EndFraction
Option A
B
StartFraction sine (51 degrees) Over 2.6 EndFraction = StartFraction sine (53 degrees) Over z EndFraction
Option B
C
StartFraction sine (76 degrees) Over 2.6 EndFraction = StartFraction sine (51 degrees) Over z EndFraction
Option C
D
StartFraction sine (76 degrees) Over 2.6 EndFraction = StartFraction sine (53 degrees) Over z EndFraction
Option D
8

Law of cosines: a2 = b2 + c2 – 2bccos(A)

Question illustration
A
72 = 82 + 112 – 2(8)(11)cos(N)
B
82 = 72 + 112 – 2(7)(11)cos(M)
C
72 = 82 + 112 – 2(8)(11)cos(P)
D
82 = 72 + 112 – 2(7)(11)cos(P)
11

What is the area of triangle ABC? Round to the nearest square unit.

Question illustration
A
8 square units
B
15 square units
C
33 square units
D
618 square units
12

Triangle RST has sides measuring 22 inches and 13 inches and a perimeter of 50 inches. What is the area of triangle RST? Round to the nearest square inch.Heron’s formula: Area

Question illustration
A
19 square inches
B
37 square inches
C
60 square inches
D
95 square inches
13

The depth of the water at the end of a pier changes periodically along with the movement of tides. On a particular day, low tides occur at 12:00 a.m. and 3:30 p.m., with a depth of 3.25 meters, while high tides occur at 7:45 a.m. and 11:15 p.m., with a depth of 8.75 meters. Which of the following equations models d, the depth of the water in meters, as a function of time, t, in hours? Let t = 0 be 12:00 a.m.

A
d = negative 3.75 cosine (StartFraction 4 pi Over 31 EndFraction t) + 5
Option A
B
d = negative 3.75 cosine (StartFraction 4 pi Over 29 EndFraction t) + 5
Option B
C
d = negative 2.75 cosine (StartFraction 4 pi Over 31 EndFraction t) + 6
Option C
D
d = negative 2.75 cosine (StartFraction 4 pi Over 29 EndFraction t) + 6
Option D
15

The depth of the water at the end of a pier changes periodically along with the movement of tides. On a particular day, low tides occur at 12:00 a.m. and 3:30 p.m., with a depth of 3.25 meters, while high tides occur at 7:45 a.m. and 11:15 p.m., with a depth of 8.75 meters. Which of the following equations models d, the depth of the water in meters, as a function of time, t, in hours? Let t = 0 be 12:00 a.m.

A
d = negative 3.75 cosine (StartFraction 4 pi Over 31 EndFraction t) + 5
Option A
B
d = negative 3.75 cosine (StartFraction 4 pi Over 29 EndFraction t) + 5
Option B
C
d = negative 2.75 cosine (StartFraction 4 pi Over 31 EndFraction t) + 6
Option C
D
d = negative 2.75 cosine (StartFraction 4 pi Over 29 EndFraction t) + 6
Option D
16

What is the approximate value of b, rounded to the nearest tenth? Use the law of sines to find the answer.

Question illustration
A
1.9 units
B
4.7 units
C
5.0 units
D
5.7 units
17

Law of sines:

Question illustration
A
StartFraction sine (51 degrees) Over 2.6 EndFraction = StartFraction sine (76 degrees) Over z EndFraction
Option A
B
StartFraction sine (51 degrees) Over 2.6 EndFraction = StartFraction sine (53 degrees) Over z EndFraction
Option B
C
StartFraction sine (76 degrees) Over 2.6 EndFraction = StartFraction sine (51 degrees) Over z EndFraction
Option C
D
StartFraction sine (76 degrees) Over 2.6 EndFraction = StartFraction sine (53 degrees) Over z EndFraction
Option D
18

The average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year, m, can be modeled by the equation , where m = 0 represents January 1, m = 1 represents February 1, m = 2 represents March 1, and so on. Which equation also models this situation?

Question illustration
A
t = negative 35 sine (StartFraction pi Over 6 EndFraction m) + 55
Option A
B
t = negative 35 sine (StartFraction pi Over 6 EndFraction (m + 3)) + 55
Option B
C
t = 35 sine (StartFraction pi Over 6 EndFraction m) + 55
Option C
D
t = 35 sine (StartFraction pi Over 6 EndFraction (m + 3)) + 55
Option D
19

The height, h, in feet of a ball suspended from a spring as a function of time, t, in seconds can be modeled by the equation . What is the height of the ball at its equilibrium?

Question illustration
A
a feet
B
b feet
C
h feet
D
k feet
20

The average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year, m, can be modeled by the equation graphed below, where m = 0 represents January 1, m = 1 represents February 1, m = 2 represents March 1, and so on. If the equation is , what are the values of a and k?

Question illustration
A
a = –60; k = 20
B
a = –50; k = 30
C
a = –30; k = 50
D
a = –20; k = 60

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