What is the axis of symmetry of h(x) = 6x2 − 60x + 147?

For a quadratic in the form ax² + bx + c, the axis of symmetry is x = −b/(2a). Here a = 6 and b = −60, so x = −(−60)/(2·6) = 60/12 = 5. The axis of symmetry is x = 5, choice D.

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