A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?

A quadratic has exactly one real solution when its discriminant, b² − 4ac, equals 0. For choice C, a = −2, b = −4, and c = −2, so the discriminant is (−4)² − 4(−2)(−2) = 16 − 16 = 0. Therefore, 0 = −2x² − 4x − 2 has one real solution.

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