For students majoring in Hospitality Management, it was determined that 5% have visited 1–10 states, 16% have visited 11–20 states, 45% have visited 21–30 states, 19% have visited 31–40 states, and 15% have visited 41–50 states. Suppose a Hospitality Management student is randomly picked. What is the probability that the student has visited 30 or fewer states?
“30 or fewer states” includes the groups who visited 1–10, 11–20, and 21–30 states. Add their probabilities: 0.05 + 0.16 + 0.45 = 0.66. Therefore, the probability is 0.66, choice C.
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