AnswersFL-1206310-Geometry Sem 1Unit Test

Unit Test — Unit test Answers

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is the angle bisector of YEX and the perpendicular bisector of . is the angle bisector of YGZ and the perpendicular bisector of . is the angle bisector of ZFX and the perpendicular bisector of . Point A is the intersection of , , and .

Question illustration
A
Point A is the center of the circle that passes through points E, F, and G but is not the center of the circle that passes through points X, Y, and Z.
B
Point A is the center of the circle that passes through points X, Y, and Z but is not the center of the circle that passes through points E, F, and G.
C
Point A is the center of the circle that passes through points E, F, and G and the center of the circle that passes through points X, Y, and Z.
D
Point A is not necessarily the center of the circle that passes through points E, F, and G or the center of the circle that passes through points X, Y, and Z.
2
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Which diagram shows possible angle measures of a triangle?

Question illustration
A
A triangle has angle lengths 35 degrees, 115 degrees, and 25 degrees.
Option A
B
A triangle has angle lengths 32 degrees, 115 degrees, and 33 degrees.
Option B
C
A triangle has angle lengths 35 degrees, 120 degrees, and 35 degrees.
Option C
D
a triangle has angle lengths 30 degrees, 120 degrees, and 20 degrees.
Option D
3

In the triangles, HG = MP and GK = PN.

Question illustration
A
mG > mP
Option A
B
mP > mG
Option B
C
HK = MN
D
HG = PN
4

Triangle DEF is isosceles, where . Angle FDE is bisected by segment DG, creating angle GDE with a measure of 29°.

Question illustration
A
29°
B
32°
C
58°
D
64°
5

The base angle of an isosceles triangle measures 54°. What is the measure of its vertex angle?

2
27°
3
36°
5
54°
7
72°
6

A triangle with exterior angles is shown. The bottom right angle of the triangle is (3 h + 18) degrees. The bottom right exterior angle is (15 h) degrees.

Question illustration
A
h = 1.5
B
h = 9
C
h = 10
D
h = 13.5
7

Consider the triangle.

Question illustration
A
mA = 95°, mB = 53°, mC = 32°
Option A
B
mA = 32°, mB = 53°, mC = 95°
Option B
C
mA = 43°, mB = 32°, mC = 95°
Option C
D
mA = 53°, mB = 95°, mC = 32°
Option D
8

Lines P S and W T are horizontal and parallel. Lines V R and Q R are diagonal and intersect lines P S and W T to form triangle X Y Z.

Question illustration
A
∠RXZ and ∠YXZ
B
∠PXQ and ∠RXS
C
∠YZX and ∠UZT
D
∠WZX and ∠XYZ
9

In triangle QRS, QR = 8 and RS = 5. Which expresses all possible lengths of side QS?

Q
QS = 13
5
5 < QS < 8
Q
QS > 13
3
3 < QS < 13
10

Triangle ABC has the angle measures shown.

Question illustration
A
Measure of angle A = 20 degrees
Option A
B
Measure of angle B = 60 degrees
Option B
C
are complementary
Option C
D
Measure of angle A + measure of angle C = 120 degrees
Option D
11

[Figure may not be drawn to scale]

Question illustration
A
12 mm
B
24 mm
C
36 mm
D
48 mm
12

A triangle has side lengths measuring 2x + 2 ft, x + 3 ft, and n ft.

A
x – 1 < n < 3x + 5
B
n = 3x + 5
C
n = x – 1
D
3x + 5 < n < x – 1
13

In the triangles, and .

Question illustration
A
mC = mS
Option A
B
mC < mS
Option B
C
mC > mS
Option C
D
mC ≥ mS
Option D
14

Triangle A B C is shown. Lines are drawn from each point to to the opposite side and intersect at point G. Line segments A D, B E, and C F are created.

Question illustration
A
Point G cannot be the centroid because 18:6 does not equal 2:1.
B
Point G cannot be the centroid because FG should be longer than CG.
C
Point G can be the centroid because 12:6 equals 2:1.
D
Point G can be the centroid because FC is longer than FG.
15

Which type of triangle will always have a perpendicular bisector that is also an angle bisector?

A
right
B
scalene
C
obtuse
D
equilateral
16

[Figure may not be drawn to scale]

Question illustration
A
25 units
B
50 units
C
100 units
D
150 units
17

Point Z is equidistant from the vertices of ΔTUV.

Question illustration
A
Line segment T A is-congruent-to line segment T B
Option A
B
Line segment A Z is-congruent-to line segment B Z
Option B
C
BTZ BUZ
Option C
D
TZA TZB
Option D
18

Point Z is the circumcenter of ΔTUV.

Question illustration
A
23.7°
B
32.8°
C
33.5°
D
57.2°
19

Triangle J K L is shown. Lines are drawn from each point to the opposite side and intersect at point P. Line segments J O, K M, and L N are created.

Question illustration
A
LN ⊥ JK, JO ⊥ LK, and JL ⊥ MK.
B
JL = LK = KJ
C
JM = ML, LO = OK, and KN = NJ.
D
LN is a perpendicular bisector of JK, JO is a perpendicular bisector of LK, and MK is a perpendicular bisector of JL.
20

Equilateral triangle ABC has a perimeter of 96 millimeters. A perpendicular bisector is drawn from angle A to side at point M.What is the length of ?

Question illustration
A
16 mm
B
24 mm
C
32 mm
D
48 mm

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