AnswersCA-Statistics and Probability BEstimating the Difference between Two Population Proportions

Estimating the Difference between Two Population Proportions — Unit test Answers

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What is the z* critical value for constructing a 95% confidence interval for a proportion?Find the z-table here.

A
1.65
B
1.96
C
2.33
D
2.58
2
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A political candidate feels that she performed particularly well in the most recent debate against her opponent. Her campaign manager polled a random sample of 400 likely voters before the debate and a random sample of 500 likely voters after the debate. The 95% confidence interval for the true difference (post-debate minus pre-debate) in proportions of likely voters who would vote for this candidate was (–0.014, 0.064). What was the difference (pre-debate minus post-debate) in the sample proportions of likely voters who said they will vote for this candidate?

A
StartFraction 0.064 + (negative 0.014) Over 2 EndFraction = 0.025
Option A
B
StartFraction 0.064 minus (negative 0.014) Over 2 EndFraction = 0.039
Option B
C
0.064 + (–0.014) = 0.050
D
0.064 – (–0.014) = 0.078
3

After a hailstorm, a large car dealership wants to determine the proportion of cars that have damage. The service department randomly selects 50 cars on the dealership lot, examines them, and finds that 11 cars have damage. They want to construct a 99% confidence interval for the true proportion of cars with damage from the storm. Are the conditions for inference met?

A
Yes, the conditions for inference are met.
B
No, the 10% condition is not met.
C
No, the randomness condition is not met.
D
No, the Large Counts Condition is not met.
4

A random sample of high school seniors was surveyed about whether they drive to school. Of the 75 seniors surveyed, 64 stated they drive to school. Which of the following is the 90% confidence interval for p, the proportion of all high school seniors who drive to school?Find the z-table here.

A
(0.80, 0.91)
B
(0.79, 0.92)
C
(0.77, 0.93)
D
(0.75. 0.96)
5

The school board of a large school district would like to raise taxes in the district to pay for new computers. To see if there is support for a tax increase, they send a survey home with a random sample of students in the district. If the survey is not completed, calls are made to ensure responses are obtained from the parents of every selected student. The survey asks, "Would you be in favor of a modest tax increase to fund the purchase of new computers for all students?” The confidence interval for the true proportion of families that are in favor of a tax increase is 0.70 to 0.80. Members of the community who do not have children in the district complain about not being included in this study. Which of the following sources of bias affected the confidence interval, but is not included among the sources covered by the margin of error?

A
wording bias
B
response bias
C
nonresponse bias
D
undercoverage bias
6

A major car dealership has several stores in a big city. The owner wants to determine if there is a difference in the proportions of SUVs that are sold at stores A and B. The owner gathers the sales records for each store from the past year. A random sample of 55 receipts from store A shows that 30 of the sales were for SUVs. Another random sample of 60 receipts from store B shows that 45 of the sales were for SUVs.Based on the 99% confidence interval, (–0.43, –0.02), is there convincing evidence of a difference in the proportions of sales that are SUVs for the two stores?

A
There is convincing evidence because the entire interval is below 0.
B
There is convincing evidence because the two sample proportions are different.
C
There is not convincing evidence because another confidence interval that uses a higher level of confidence might contain 0.
D
There is not convincing evidence because two different sample sizes were used. In order to determine a difference, the same number of sale records should be selected from each population.
7

A school nurse would like to estimate the true mean amount of sleep that students at the high school get per night. To do so, she selects a random sample of 30 students and determines that the 90% confidence interval for the true mean number of hours of sleep that high school students get per night to be 6.5 to 7.5 hours. Which of these statements is a correct interpretation of the confidence level?

A
There is a probability of 0.90 that the confidence interval (6.5, 7.5) captures the true mean number of hours of sleep that high school students get per night.
B
The nurse can be 90% confident that the true mean number of hours of sleep that all students at her high school get per night is between 6.5 hours and 7.5 hours.
C
If many random samples of size 30 are selected from the population of all students at this high school, approximately 90% of the sample means will be between 6.5 and 7.5 hours.
D
If many random samples of size 30 are selected from the population of all students, about 90% of the intervals would capture the true mean number of hours of sleep that students of this high school get per night.
8

A political candidate feels that she performed particularly well in the most recent debate against her opponent. Her campaign manager polled a random sample of 400 likely voters before the debate and a random sample of 500 likely voters after the debate. The 95% confidence interval for the true difference (post-debate minus pre-debate) in proportions of likely voters who would vote for this candidate was (–0.014, 0.064). Based on this interval, what conclusion should the candidate make about the proportion of likely voters who would vote for her in the upcoming election?

A
There is a 95% chance that the proportion who would vote for her has increased.
B
The candidate cannot conclude that the proportion of likely voters who would vote for her has increased.
C
It can be stated with 95% confidence that there was no change in the proportion who would vote for her.
D
It can be stated with 95% confidence that there is convincing evidence that the proportion who would vote for her has increased.
9

Nick selects a simple random sample of 25 seniors at his large school and finds that 20 of them eat a healthy breakfast. He wants to construct a confidence interval for p = the proportion of all seniors at this school who eat a healthy breakfast, but he realizes he hasn’t met all the conditions for constructing the interval. Which condition for this procedure has he failed to meet?

A
n≥30
B
n p hat greater-than-or-equal-to 10
Option B
C
n (1 minus p hat) greater-than-or-equal-to 10
Option C
D
The sample size must be less than 10% of the population size.
10

A statistics student wants to survey a high school of 910 students concerning support for increasing the number of student parking spots. The student randomly selects 100 students to construct a 95% confidence interval for the true proportion of students who support increasing the number of student parking spots, and finds that 77 students are in support. Are the conditions for inference met?

A
Yes, the conditions for inference are met.
B
No, the 10% condition is not met.
C
No, the randomness condition is not met.
D
No, the Large Counts Condition is not met.
11

A school nurse would like to estimate the true mean amount of sleep that students at the high school get per night. To do so, she selects a random sample of 30 students and determines that the 90% confidence interval for the true mean amount of sleep that high school students get per night to be 6.5 to 7.5 hours. Which of the following would decrease the width of the interval?

A
selecting another sample
B
decreasing the sample size
C
increasing the confidence level
D
decreasing the confidence level
12

The cafeteria manager at a high school that has 910 students and 75 teachers is considering adding a baked potato bar to the lunch menu. The manager randomly surveys 90 students and 25 teachers, and finds that 50 of the 90 students and 13 of the 25 teachers would purchase from the potato bar. The manager constructs a 99% confidence interval for the difference in the proportions of students and teachers who would purchase lunch on the day the potato bar option is available. Are the conditions for inference met?

A
Yes, the conditions for inference are met.
B
No, the 10% condition is not met.
C
No, the randomness condition is not met.
D
No, the Large Counts Condition is not met.
13

Twenty-four pairs of adult brothers and sisters were sampled at random from a population. The difference in heights, recorded in inches (brother’s height minus sister’s height), was calculated for each pair. The 95% confidence interval for the mean difference in heights for all brother-and-sister pairs in this population was (–0.76, 4.34). What is the margin of error for the confidence interval?

A
StartFraction 4.34 minus 0.76 Over 2 EndFraction = 1.79
Option A
B
StartFraction 4.34 minus (negative 0.76) Over 2 EndFraction = 2.55
Option B
C
4.34 – 0.76 = 3.58
D
4.34 – (–0.76) = 5.10
14

A statistics class weighed 20 bags of grapes purchased from the store. The bags are advertised to contain 16 ounces, on average. The class calculated the 90% confidence interval for the true mean weight of bags of grapes from this store to be (15.875, 16.595) ounces. What is the correct interpretation of the 90 percent confidence interval?

A
90% of the bags of grapes in the sample weigh 16 ounces.
B
90% of the bags of grapes in the sample weigh between 15.875 and 16.595 ounces.
C
We are 90% confident that the interval from 15.875 ounces to 16.595 ounces captures the true mean weight of bags of grapes.
D
If many samples of size 20 were taken, and confidence intervals created for each sample, 90% of those confidence intervals would contain the true mean weight of bags of grapes.
15

The owner of a popular coffee shop wants to determine if there is a difference between the proportion of customers who use their own cups when they purchase a coffee beverage, and the proportion of customers who use their own cups when they purchase an espresso beverage. Customers using their own cups get a 5% discount, which is displayed on the receipt. The owner randomly selects 50 receipts from all coffee purchases and 50 receipts from all espresso purchases. For coffee purchases, 24 receipts showed that the customer used their own cup. For espresso purchases, 18 receipts showed that the customer used their own cup. Assuming the conditions for inference have been met, what is the 99% confidence interval for the difference in proportion of customers who use their own cups?Find the z-table here.

A
(0.48 minus 0.36) plus-or-minus 2.58 StartRoot StartFraction 0.48 (1 minus 0.48) Over 50 EndFraction + StartFraction 0.36 (1 minus 0.36) Over 50 EndFraction EndRoot
Option A
B
(0.48 minus 0.36) plus-or-minus 2.33 StartRoot StartFraction 0.48 (1 minus 0.48) Over 50 EndFraction + StartFraction 0.36 (1 minus 0.36) Over 50 EndFraction EndRoot
Option B
C
(0.52 minus 0.64) plus-or-minus 2.58 StartRoot StartFraction 0.52 (1 minus 0.52) Over 100 EndFraction + StartFraction 0.64 (1 minus 0.64) Over 100 EndFraction EndRoot
Option C
D
(0.52 minus 0.64) plus-or-minus 2.33 StartRoot StartFraction 0.52 (1 minus 0.52) Over 100 EndFraction + StartFraction 0.64 (1 minus 0.64) Over 100 EndFraction EndRoot
Option D

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