AnswersPMHS Geometry Q2Using Triangle Congruence Theorems

Using Triangle Congruence Theorems — Unit test Answers

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On a coordinate plane, 2 triangles are shown. Triangle A B C has points (negative 3, negative 1), (negative 1, 2), and (negative 5, 3). Triangle R S T has points (1, 1), (3, 4), and (5, 0).

Question illustration
A
ΔRST ≅ ΔACB
B
ΔRST ≅ ΔABC
C
ΔRST ≅ ΔBCA
D
ΔRST ≅ ΔBAC
2
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Triangles D E F and D prime E prime F prime are connected at point E. Triangle D E F is rotated about point E to form triangle D prime E prime F prime.

Question illustration
A
dilation
B
reflection
C
rotation
D
translation
3

Which pair of triangles can be proven congruent by SAS?

A
2 triangles with identical angle measures are shown. The second triangle is shifted to the right.
Option A
B
2 triangles are shown. They have 2 congruent sides and a congruent angle. The first triangle is rotated about a point to form the second triangle.
Option B
C
2 triangles are shown. They have 1 congruent side and 2 congruent angles. The first triangle is rotated about a shared side to form the second triangle.
Option C
D
Option
Option D
4

Which congruence theorem can be used to prove △BDA ≅ △DBC?

Question illustration
A
HL
B
SAS
C
AAS
D
SSS
5

Triangles A B C and D E F are shown. Triangle A B C is rotated to the left about point A and then is shifted up and to the right to form triangle D E F.

Question illustration
A
Translate vertex A to vertex D, and then reflect △ABC across the line containing AC.
B
Translate vertex B to vertex D, and then rotate △ABC around point B to align the sides and angles.
C
Translate vertex B to vertex D, and then reflect △ABC across the line containing AC.
D
Translate vertex A to vertex D, and then rotate △ABC around point A to align the sides and angles.
6

In the triangles, HG = MP and GK = PN.

Question illustration
A
mG > mP
Option A
B
mP > mG
Option B
C
HK = MN
D
HG = PN
7

Triangle DEF is isosceles, where . Angle FDE is bisected by segment DG, creating angle GDE with a measure of 29°.

Question illustration
A
29°
B
32°
C
58°
D
64°
8

On a coordinate plane, 2 triangles are shown. Triangle A B C has points (negative 1, negative 1), (2, negative 1), and (negative 1, negative 5). Triangle R S T has points (1, 1), (1, 5), and (4, 1).

Question illustration
A
The figures are congruent. ΔRST can be mapped to ΔACB by a reflection over the x-axis and a translation 2 units to the left.
B
The figures are congruent. ΔRST can be mapped to ΔACB by a reflection over the y-axis and a translation 2 units down.
C
The figures are not congruent. Point R corresponds to point A, but S corresponds to B and T corresponds to C.
D
The figures are not congruent. Point R does not correspond with point A.
9

A triangle has side lengths measuring 2x + 2 ft, x + 3 ft, and n ft.

A
x – 1 < n < 3x + 5
B
n = 3x + 5
C
n = x – 1
D
3x + 5 < n < x – 1
10

Triangles W X Z and Y Z X share common side X Z. Angles W X Z and X Z Y are right angles. The lengths of sides W X and Z Y are 21 centimeters.

Question illustration
A
Yes, they are congruent by SAS.
B
Yes, they are both right triangles.
C
No, the triangles share side XZ.
D
No, there is only one set of congruent sides.
11

Triangles A B C and E D C are shown. Triangle A B C is rotated about point C to form triangle E D C.

Question illustration
A
a rotation about point B
B
a reflection across the line containing CB
C
a reflection across the line containing AC
D
a rotation about point C
12

The proof that UX ≅ SV is shown.Given: △STU an equilateral triangle∠TXU ≅ ∠TVSProve: UX ≅ SVWhat is the missing statement in the proof?StatementReason1. ∠TXU ≅ ∠TVS1. given2. ∠STV ≅ ∠UTX2. reflex. prop.3. △STU is an equilateral triangle3. given4. ST ≅ UT4. sides of an equilat. △ are ≅5. ?5. AAS6. UX ≅ SV6. CPCTC

Question illustration
A
△SXU ≅ △TVS
B
△UVX ≅ △SXV
C
△SWX ≅ △UWV
D
△TUX ≅ △TSV

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