Answers690201 Geometry S1 – NEMECEK ANGELLA SUnit Test

Unit Test — Unit test Answers

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Triangle DEF was tranformed to create triangle D'E'F'. Complete the statement about the transformation.

Question illustration
A
point D.
B
point E'.
C
point F.
D
point E.
2
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Which rules could describe the rotation? Select two options.

A
R0, 90°
B
R0, 180°
C
R0, 270°
D
(x, y) → (–y, x)
E
(x, y) → (y, –x)
3

A transformation of ΔDEF results in ΔD'E'F'.

Question illustration
A
The transformation is a dilation.
B
The transformation is a reflection.
C
The transformation is a rotation.
D
The transformation is a translation.
4

Square PQRS is transformed as shown on the graph.

Question illustration
A
R0, 90°
B
R0, 180°
C
R0, 270°
D
R0, 360°
5

A square on a coordinate plane is translated 9 units down and 1 unit to the right. Which function rule describes the translation?

A
T1, –9(x, y)
B
T–1, –9(x, y)
C
T–9, 1(x, y)
D
T–9, –1(x, y)
6

What mistakes did he make? Select two options.

A
He applied the reflection to the pre-image first.
B
He applied the rotation to the pre-image first.
C
He changed the size of the figure instead of just applying a rotation.
D
He used point P as the center of rotation.
E
He used an incorrect angle of rotation around point P.
7

Triangle ABC was transformed to create triangle DEF.

Question illustration
A
corresponds to because they are about the same length.
Option A
B
corresponds to because they are in the same position.
Option B
C
corresponds to because the transformation is isometric.
Option C
D
corresponds to because the length is not preserved.
Option D
8

A point has the coordinates (m, 0) and m ≠ 0.Which reflection of the point will produce an image located at (0, –m)?

A
a reflection of the point across the x-axis
B
a reflection of the point across the y-axis
C
a reflection of the point across the line y = x
D
a reflection of the point across the line y = –x
9

Polygon LMNOP was transformed to create polygon L'M'N'O'P'.

Question illustration
A
Angle
Option A
B
Angle
Option B
C
Angle
Option C
D
Angle
Option D
10

On a coordinate plane, 3 triangles are shown. Triangle A B C has points (5, negative 5), (1, negative 2), (1, negative 5). Triangle A prime B prime C prime has points (5, 5), (1, 2), (1, 5). Triangle A double-prime B double-prime C double prime has points (negative 1, 3), (negative 5, 0), (negative 5, 3).

Question illustration
A
Translation of negative 6 units x, negative 2 units y composition reflection across the x-axis
Option A
B
Reflection across the x-axis composition translation of negative 6 units x, negative 2 units y
Option B
C
Translation of negative 6 units x, negative 2 units y composition 90 degree rotation about point 0
Option C
D
90 degree rotation about point 0 translation of negative 6 units x, negative 2 units y
Option D
11

On a coordinate plane, 2 triangles are shown. The first triangle has points F (3, 2), H (4, 5), G (1, 2). The second triangle has points F prime (negative 2, 3), H prime (negative 5, 4), G prime (negative 2, 1).

Question illustration
A
Correct. He transformed the triangle according to the rule (x, y) → (–y, x).
B
Incorrect. He transformed the triangle according to the rule (x, y) → (y, –x)
C
Incorrect. He transformed the triangle according to the rule (x, y) → (–y, –x)
D
Incorrect. He transformed the triangle according to the rule (x, y) → (–x, –y)
12

On a coordinate plane, a triangle has points R (negative 3, 4), T (negative 1, negative 4), and S (negative 4, negative 2).

Question illustration
A
(–4, 3)
B
(4, –3)
C
(–3, –4)
D
(3, 4)
13

Figure R S T U V is reflected across a point of reflection n to form R prime S prime T prime U prime V prime. Figure R prime S prime T prime U prime V prime is rotated 270 degrees about point P to form R double-prime S double-prime T double-prime U double-prime V double-prime

Question illustration
A
a reflection across line n followed by a translation down and to the right
B
a reflection across line n followed by a 270° rotation about point P
C
a translation down followed by a 270° rotation about point P
D
a translation down followed by a reflection across line n
14

On a coordinate plane, 5 trapezoids are shown. Trapezoid L M N P is in quadrant 2 and has points (negative 2, 3), (negative 2, 6), (negative 1, 6), and (negative 1, 4). Trapezoid B is reflected in quadrant 2. Trapezoid C is reflected across the y-axis. Trapezoid D is reflected into quadrant 4. Trapezoid A is reflected across the x-axis.

Question illustration
A
figure A
B
figure B
C
figure C
D
figure D
15

Triangle EFG has vertices E(–3, 4), F(–5, –1), and G(1, 1). The triangle is translated so that the coordinates of the image are E’(–1, 0), F’(–3, –5), and G’(3, –3).

A
T4, –4(x, y)
B
T–4, –4(x, y)
C
T2, –4(x, y)
D
T–2, –4(x, y)

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