Question 17 • Algebra 2 Sem 1 (1200330)BCPS 2025-26
With zeros at 6 and 42, the quadratic has the form y = a(x − 6)(x − 42). Using the point (15, 81), 81 = a(9)(−27), so a = −1/3. Expanding gives y = −1/3x² + 16x − 84. Values above the boundary have greater y-values, so the inequality is y > −1/3x² + 16x − 84, choice B.
AI-written and checked against the verified answer.