A commuter train is late to a station 5% of the time. Last week, the train was late on 2 of the 7 days. If the train being late can be considered a random event, what is the probability that the train would be late 2 times in 7 days?

Use the binomial probability for exactly 2 late days out of 7: choose which 2 days are late, then multiply by the probability of 2 late days and 5 on-time days. This gives C(7,2)(0.05)^2(0.95)^5 = 21(0.0025)(0.7738) ≈ 0.0406, which rounds to 0.041. The correct choice is C, 0.041.

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