At a certain pizzeria, it is known that 12% of orders are for extra-large pizzas. What is the probability that the 6th pizza ordered is the first extra-large pizza?

For the 6th pizza to be the first extra-large, the first 5 pizzas must not be extra-large and the 6th must be. Each pizza has a 12% chance of being extra-large, so the probability is (0.88)^5 × 0.12 ≈ 0.0633. Therefore, the correct choice is A, 0.0633.

AI-written and checked against the verified answer.