Question 17 • GA-Advanced Algebra: Concepts and Connections CR
Test whether the mean exceeds $150: the null hypothesis is μ = $150 and the alternative is μ > $150. The standard error is $30.20/√40 ≈ $4.78, so the test statistic is ($160 − $150)/$4.78 ≈ 2.09. For a one-tailed test at the 2.5% significance level, the critical z-value is about 1.96; since 2.09 is greater, reject the null hypothesis. The valid conclusion is that the customers spend more than the national average in his store.
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