Question 21 • Common Core Algebra I 2014 - MA3109 B-CR
The solutions are where the two graphs intersect, so set their y-values equal: x² − 6x + 8 = −x + 4. Rearranging gives x² − 5x + 4 = 0, which factors as (x − 1)(x − 4) = 0, so x = 1 or x = 4. Substituting into y = −x + 4 gives y = 3 and y = 0, so the solution set is (1, 3) and (4, 0).
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