Question 3 • **MFISD GEOMETRY B 22-23 CR
There are 10 digits and 26 lowercase letters, for 36 possible characters total. The number of ways to choose four characters with exactly one digit is 10 × C(26, 3) = 26,000; the total number of ways to choose four distinct characters is C(36, 4) = 58,905. Thus the probability is 26,000 ÷ 58,905 ≈ 0.441, or about 44%, so the correct choice is D) 44%.
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