In a randomly generated sequence of 24 binary digits (0s and 1s), what is the probability that exactly half of the digits are 0?

Each of the 24 digits has two equally likely possibilities, so there are 2²⁴ possible sequences. To have exactly 12 zeros, choose which 12 of the 24 positions contain zeros: there are (24 choose 12) = 2,704,156 such sequences. Thus the probability is 2,704,156 ÷ 16,777,216 ≈ 0.1612, which matches choice D.

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