Question 15 • Probability and Statistics with Applications Honors Sem-2-FL-1210300 (2024-2025)
Because the population standard deviation is not given, use a t-interval with 38 − 1 = 37 degrees of freedom. For 99% confidence, the critical value is about 2.715, and the standard error is 22.1/√38 ≈ 3.58. The margin of error is 2.715 × 3.58 ≈ 9.73, so the interval is 48.2 ± 9.73, or approximately (38.47, 57.94). Thus, the 99% confidence interval is choice A.
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