Question 12 • MO-Algebra II A-CR
A circle’s equation in standard form is (x − h)² + (y − k)² = r², where its center is (h, k) and its radius is r. Here, (x + 3)² = (x − (−3))² and (y − 4)², so the center is (−3, 4). Since r² = 9, the radius is 3. Therefore, the graph is a circle centered at (−3, 4) with radius 3.
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