3
QuizMultiple Choice

Unit Test — Unit test

Question 3 • CREDIT RE-SEAT MNPS Integrated Math III IC S1 25-26

Which polynomial function has a leading coefficient of 2, root –5 with multiplicity 3, and root 12 with multiplicity 1?

Answer
A
f(x) = 2(x – 5)(x – 5)(x – 5)(x + 12)
B
f(x) = 2(x + 5)(x + 5)(x + 5)(x – 12)
C
f(x) = 3(x – 5)(x – 5)(x + 12)
D
f(x) = 3(x + 5)(x + 5)(x – 12)

Explanation

A root r gives a factor of (x − r), repeated according to its multiplicity. Root −5 with multiplicity 3 gives (x + 5)³, and root 12 with multiplicity 1 gives (x − 12). Multiplying these factors by the leading coefficient 2 gives 2(x + 5)³(x − 12), which is choice B.

AI-written and checked against the verified answer.

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