Question 7 • *Integrated Math II Full
A quadratic with a maximum of $18,050 at 105 units has vertex form f(x)=a(x−105)²+18,050, where a is negative. Since profit is 0 when 10 units are sold, substitute x=10: 0=a(10−105)²+18,050. Thus 9,025a=−18,050, so a=−2. Therefore the function is f(x)=−2(x−105)²+18,050, choice B.
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