A 20.0 kg object is at rest, and then speeds up to 16.0 m/s. How much work was done on this system?

The work done on the object equals its change in kinetic energy. Starting from rest, its initial kinetic energy is 0 J, and its final kinetic energy is ½(20.0 kg)(16.0 m/s)² = 2,560 J. Therefore, the work done was 2,560 J, choice B.

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