Question 1 • AP Calculus AB - MA5186 A
At t = 0, the equations must give the initial point (–5, 3), and at t = 1 they must give the terminal point (1, –6). The change in x is 1 – (–5) = 6, and the change in y is –6 – 3 = –9, so the equations are x(t) = –5 + 6t and y(t) = 3 – 9t. These are choice C.
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