What is the equation of the line tangent to the function f(x) = 1 – x2 at x = –3?

Differentiate f(x) = 1 − x² to get f′(x) = −2x, so the tangent’s slope at x = −3 is 6. The point on the function is f(−3) = 1 − 9 = −8. Using point-slope form gives y + 8 = 6(x + 3), or y = 6x + 10, which is choice A.

AI-written and checked against the verified answer.