Which diagram shows lines that must be parallel lines cut by a transversal?




Given: and Prove: What is the missing reason in the proof?

Two parallel lines are crossed by a transversal.

The given line segment has a midpoint at (3, 1).



Consider the diagram.

The given line passes through the points (0, ) and (2, 3).





In the diagram, CE=12 units and BE=5 units.

In the diagram, the length of segment QV is 15 units.

On a coordinate plane, 2 lines are shown. Line H J has points (negative 4, negative 2) and (0, 4). Line F G has points (negative 4, 1) and (0, negative 2).

On a coordinate plane, line D F goes through points (negative 1, negative 3) and (2, 3). Point G is at (negative 4, negative 4).

Based on this information, which pair of lines, together, could be perpendicular to RS? Select two options.





Lines a and b are parallel lines cut by transversal f.

A given line has the equation .What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?





Horizontal lines e and f are cut by vertical lines a and b. At the intersection of lines a and e, the uppercase right angle is (x + 1) degrees. At the intersection of lines a and f, the bottom right angle is (x minus 3) degrees. At the intersection of lines b and e, the bottom left angle is y degrees.

Two parallel lines are crossed by a transversal.

On a coordinate plane, 2 lines are shown. Line C D has points (negative 2, 4) and (0, negative 4). Line F G has points (negative 4, 0) and (4, 2).

Consider the diagram.

A pipe cleaner lay across a wire shelf. The wires that make up the shelf are parallel, and the pipe cleaner is a transversal. The parallel wires are labeled a, b, and, c, and the angles are labeled with numbers.

On a coordinate plane, line A B goes through (negative 2, 4) and (0, negative 4). Point Z is at (0, 2).

On a coordinate plane, a line goes through (negative 5, negative 4) and (0, negative 3). A point is at (negative 2, 2).




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