AnswersCR CCSS Math 2 S2 M2960OXRight Triangle Similarity

Right Triangle Similarity — Unit test Answers

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Triangles A B C and A double-prime B double-prime C double-prime connect at point C. Triangle A B C is rotated and then made smaller to form triangle A double-prime B double-prime C double-prime.

Question illustration
A
a rotation and a reflection
B
a translation and a dilation
C
a reflection and a dilation
D
a dilation and a rotation
2
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On a coordinate plane, a line is drawn from point A to point B. Point A is at (9, negative 8) and point B is at (negative 6, 7).

Question illustration
A
(2, –1)
B
(4, –3)
C
(–1, 2)
D
(3, –2)
3

On a coordinate plane, Rectangles A B C D and E F G H are shown. The length of side A B is 6 units and the length of side B C is 3 units. The length of side E F is 8 units and the length of side F G is 4 units.

Question illustration
A
Yes, because corresponding sides are parallel and have lengths in the ratio
Option A
B
Yes, because both figures are rectangles and all rectangles are similar.
C
No, because the center of dilation is not at (0, 0).
D
No, because corresponding sides have different slopes.
4

Parallelogram FGHJ was dilated and translated to form similar parallelogram F'G'H'J'.

Question illustration
A
One-eighth
Option A
B
One-fourth
Option B
C
4
D
8
5

On a coordinate plane, a line is drawn from Rock to Tree. The x- and y-axes are labeled feet. Rock is at (3, 2) and Tree is at (16, 21).

Question illustration
A
(11.4, 14.2)
B
(7.6, 8.8)
C
(5.7, 7.5)
D
(10.2, 12.6)
6

Read the proof.Given: AB ∥ DEProve: △ACB ~ △DCE

Question illustration
A
AA similarity theorem.
B
SSS similarity theorem.
C
AAS similarity theorem.
D
ASA similarity theorem.
7

Triangle N T M is shown. Angle N T M is a right angle. An altitude is drawn from point T to point U on side N M to form a right angle. The length of N T is y, the length of T M is 6, the length of N U is 9, and the length of U M is 3.

Question illustration
A
units
Option A
B
units
Option B
C
units
Option C
D
units
Option D
8

Triangle L M N is cut by line segment O P. Line segment O P goes from side M L to side M N. The length of O L is 14, the length of O M is 28, the length of M P is y, and the length of P N is 18.

Question illustration
A
16
B
24
C
32
D
36
9

Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right angle. The length of S T is 9 and the length of T Q is 16. The length of R T is x.

Question illustration
A
12 units
B
15 units
C
20 units
D
25 units
10

Question text not available

Question illustration
A
3 ft
B
4 ft
C
18 ft
D
12 ft
11

Quadrilateral JKLM was dilated according to the ruleDO,(x,y) to create the image quadrilateral J'K'L'M', which is shown on the graph.

Question illustration
A
(0, -4)
B
(0, -1)
C
(0, 0)
D
(0, 4)
12

is an altitude in triangle WXZ.

Question illustration
A
XWZ is an obtuse angle.
Option A
B
XWZ is a right angle.
Option B
C
XWZ is congruent to WXY.
Option C
D
XWZ is congruent to XZW.
Option D
13

Triangle TVW is dilated according to the ruleDO,(x,y) to create the image triangle T'V'W', which is not shown.

Question illustration
A
T'(-3, 6) and V'(0, 3)
B
T'(-3, 6) and V'(0, 1)
C
T'(-1, 2) and V'(0, 3)
D
T'(-1, 2) and V'(0, 1)
14

Triangle R Q S is cut by line segment T V. Line segment T V goes from side Q R to side R S. The length of R V is x + 10, the length of V S is x, the length of R T is x + 4, and the length of T Q is x minus 3.

Question illustration
A
3
B
8
C
10
D
11
15

Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right angle. The length of T Q is 16 and the length of R Q is 20.

Question illustration
A
9 units
B
12 units
C
15 units
D
18 units
16

If point P is of the distance from M to N, what ratio does the point P partition the directed line segment from M to N into?

Question illustration
A
4:1
B
4:3
C
4:7
D
4:10
17

Which best explains why all equilateral triangles are similar?

A
All equilateral triangles can be mapped onto each other using dilations.
B
All equilateral triangles can be mapped onto each other using rigid transformations.
C
All equilateral triangles can be mapped onto each other using combinations of dilations and rigid transformations.
D
All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
18

and are midsegments of ΔWXY.

Question illustration
A
11.57 cm
B
12.22 cm
C
12.46 cm
D
14.50 cm
19

On a number line, the directed line segment from Q to S has endpoints Q at –14 and S at 2. Point R partitions the directed line segment from Q to S in a 3:5 ratio.Which expression correctly uses the formula to find the location of point R?

Question illustration
A
(StartFraction 3 Over 3 + 5 EndFraction) (2 minus (negative 14)) + (negative 14)
Option A
B
(StartFraction 3 Over 3 + 5 EndFraction) (negative 14 minus 2) + 2
Option B
C
(StartFraction 3 Over 3 + 5 EndFraction) (2 minus 14) + 14
Option C
D
StartFraction 3 Over 3 + 5 EndFraction (negative 14 minus 2) minus 2
Option D
20

Triangles L M N and P O N connect at point N. Angles L M N and N O P are congruent.

Question illustration
A
because both triangles appear to be equilateral
B
because∠MNL and ∠ONP are congruent angles
C
because one pair of congruent corresponding angles is sufficient to determine similar triangles
D
because both triangles appear to be isosceles, ∠MLN ≅ ∠LMN, and ∠NOP ≅ ∠OPN

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