Question 6 • (AG Q3) Math 8: 25-26 (JTurner)
Adding the equations cancels the x-terms: 2x + (−2x) = 0. The y-terms give −8y + 4y = −4y, so the result is −4y = −8 and y = 2; it is not −12y = −8. Substituting y = 2 into 2x − 8y = 0 gives 2x − 16 = 0, so x = 8. Thus the true statements are that x cancels, y = 2, and x = 8; the solution is (8, 2), not (2, 8).
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