AnswersPre-Algebra BConstructing Scatterplots

Using Equations to Represent Trend Lines Answers

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Which pair of points should be used to find the line of best-fit for the scatterplot?.

Question illustration
A
J and L
B
J and M
C
K and L
D
K and M
2
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Which expression can be simplified to find the slope of the trend line in the scatterplot?

Question illustration
A
StartFraction 24 minus 79 Over 12 minus 2 EndFraction
Option A
B
StartFraction 24 + 79 Over 12 + 2 EndFraction
Option B
C
StartFraction 24 minus 79 Over 2 minus 12 EndFraction
Option C
D
StartFraction 24 minus 79 Over 12 + 2 EndFraction
Option D
3

Loren solved the equation for b as part of her work to find the equation of a trend line that passes through the points (1, 130) and (10, 149). What error did Loren make?

Question illustration
A
She should have solved for b.
Option A
B
She should have solved for b.
Option B
C
She should have solved for b.
Option C
D
She should have solved for b.
Option D
4

What is the slope of a trend line that passes through the points (–3, 3) and (18, 26)?

A
StartFraction 15 Over 29 EndFraction
Option A
B
StartFraction 21 Over 23 EndFraction
Option B
C
StartFraction 23 Over 21 EndFraction
Option C
D
StartFraction 29 Over 15 EndFraction
Option D
5

Jordan is calculating the slope of the trend line in the scatterplot below. How can Jordan use the plot to check the reasonableness of his answer?

Question illustration
A
His slope should be positive because the coordinates of all the plotted points are positive.
B
His slope should be positive because the trend line is slanted up to the right.
C
His slope should be negative because there are plotted points not on the line.
D
His slope should be negative because the x-coordinate of each plotted point is less than the y-coordinate.
6

A basketball coach plotted data about her shooting guard’s playing time and point scoring in a scatterplot. Shooting Guard Minutes Played and Points Scored Which is the equation of the line of best-fit?

Question illustration
A
y = StartFraction 15 Over 22 EndFraction x + StartFraction 6 Over 11 EndFraction
Option A
B
y = StartFraction 15 Over 22 EndFraction x + StartFraction 43 Over 11 EndFraction
Option B
C
y = StartFraction 22 Over 15 EndFraction x minus StartFraction 86 Over 15 EndFraction
Option C
D
y = StartFraction 22 Over 15 EndFraction x minus four-fifths
Option D
7

Mia’s work to find the slope of a trend line through the points (3, 10) and (35, 91) is shown below.Mia’s WorkStep 1Step 2Step 3What was the first error that Mia made?

Question illustration
A
Mia simplified incorrectly and made the slope positive.
B
Mia subtracted in the wrong order.
C
Mia switched the numerator and the denominator.
D
Mia used subtraction instead of addition.
8

What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?

A
Negative StartFraction 15 Over 2 EndFraction
Option A
B
Negative StartFraction 2 Over 15 EndFraction
Option B
C
StartFraction 2 Over 15 EndFraction
Option C
D
StartFraction 15 Over 2 EndFraction
Option D
9

Melanie and Tracy are each finding the equation of the trend line that fits the data in the table below. Participation in the School BandYearNumber of students201048201152201255201359Melanie uses the ordered pairs (2010, 48) and (2013, 59) to find her equation. Tracy defines x as the number of years since 2010 and uses the ordered pairs (0, 48) and (3, 59) to find her equation. How will the two girls’ equations compare?

A
They will have the same slopes and the same y-intercepts.
B
They will have the same slopes but different y-intercepts.
C
They will have different slopes but the same y-intercepts.
D
They will have different slopes and different y-intercepts.
10

Which is the equation of a trend line that passes through the points (7, 450) and (14, 401)?

A
y = negative 7 x + 499
Option A
B
y = negative StartFraction 1 Over 7 EndFraction x + 451
Option B
C
y = StartFraction 1 Over 7 EndFraction x + 449
Option C
D
y = 7 x + 401
Option D

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