Using Graphs to Solve Systems Answers

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On a coordinate plane, a line goes through (negative 4, 1) and (0, 3) and another line goes through (negative 2, negative 2) and (0, negative 1).

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A
On a coordinate plane, a line goes through (negative 4, 1) and (0, 3) and another line goes through (negative 2, negative 2) and (0, negative 1).
Option A
B
On a coordinate plane, a line goes through (negative 2, 2) and (0, 3) and another line goes through (negative 2, 0) and (0, negative 1).
Option B
C
On a coordinate plane, a line goes through (negative 2, 0) and (0, negative 1).
Option C
D
On a coordinate plane, a line goes through (0, 3) and (2, 2) and another line goes through (0, negative 1) and (2, 0).
Option D
2
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Which statement is true of this system of equations?

A
Both equations are in slope-intercept form.
Option A
B
The first equation converted to slope-intercept form is y + 2x = 4.
Option B
C
The second equation converted to slope-intercept form is .
Option C
D
Neither equation is in slope-intercept form.
Option D
3

What is the solution to the system?

A
(0, 4)
B
(0, –1)
C
(3, –2)
D
(2, –1)
5

She determined that the solution is (–3, –3). Is she correct? If not, explain why.

A
Yes, she is correct.
B
No. She switched the x and y values of the intersection point when writing the solution.
C
No. She used the wrong y-intercepts when graphing the equations.
D
No. She used the wrong slopes when graphing the equations.
6

Which graph represents the solution set to this system of equations? –x + 2y = 6 and 4x + y = 3

A
On a coordinate plane, a line goes through (negative 1, negative 1) and (0, 3) and another line goes through (1, 4) and (2, 2).
Option A
B
On a coordinate plane, a line goes through (negative 4, 0) and (0, 4) and another line goes through (negative 1, 1) and (0, negative 3).
Option B
C
On a coordinate plane, a line goes through (0, 3) and (2, 4) and another line goes through (0, 3) and (1, 0).
Option C
D
On a coordinate plane, a line goes through (0, 0) and (4, 3) and another line goes through (2, 5) and (4, 4).
Option D
7

The solution to the system is .

A
(–5, –4)
B
(–2, –1)
C
(1, 6)
D
(5, 7)
9

y = 2 minus StartFraction 7 Over 3 EndFraction x

Question illustration
A
y = 7x + 2
B
y = 3x + 5
C
y = 2 minus StartFraction 7 Over 3 EndFraction x
Option C
D
y – 2 = 4x
E
3y = –9x – 6

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Using Graphs to Solve Systems Answers — AG Q3…