Let v be a vector with initial point open paren negative 5 comma negative 11 close paren and terminal point open paren 6 comma 2 close paren What is magnitude v ?

Find the vector by subtracting the initial coordinates from the terminal coordinates: (6 − (−5), 2 − (−11)) = (11, 13). Its magnitude is √(11² + 13²) = √(121 + 169) = √290, so the correct choice is square root of 290.

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