Where is the hole for the following function located? f of x is equal to the fraction with numerator x plus 3 and denominator open paren x minus 4 close paren times open paren x plus 3 close paren

The factor x + 3 appears in both the numerator and denominator, so it cancels when simplifying: f(x) = 1/(x − 4), but the original function is still undefined at x = −3. That creates a hole at x = −3 (with y-coordinate −1/7). The correct choice is x = negative 3.

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