The zeroes of f(x) = x3 + 3x2 + 2x are .

Factor the polynomial: f(x) = x³ + 3x² + 2x = x(x² + 3x + 2) = x(x + 1)(x + 2). Setting each factor equal to zero gives x = 0, x = –1, and x = –2, so the zeroes are –2, –1, and 0, choice C.

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