A rectangular piece of iron has sides with lengths of 7.08 × 10–3 m, 2.18 × 10–2 m, and 4.51 × 10–3 m. What is the volume of the piece of iron?

The volume is the product of the three side lengths: (7.08 × 10⁻³)(2.18 × 10⁻²)(4.51 × 10⁻³) m³. Multiply the coefficients to get about 69.6, and add the exponents to get −8, giving 69.6 × 10⁻⁸ = 6.96 × 10⁻⁷ m³. Therefore, the volume is 6.96 × 10⁻⁷ m³, choice A.

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