The equation of a line in point-slope form isy – 5 = 3(x + 1). A point that lies on this line is .

The equation is in point-slope form, y − y₁ = m(x − x₁), so it identifies the point (x₁, y₁) = (−1, 5). Substituting x = −1 makes the right side 3(−1 + 1) = 0, so y = 5. Therefore, (−1, 5) lies on the line.

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