AnswersGA-Algebra Concepts and Connections ASpecial Linear Relationships

Special Linear Relationships Answers

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1
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The equation –3y = 15 – 4x rewritten in slope-intercept form is .

A
y = –(4/3)x – 5
B
y= –(4/3)x + 5
C
y = (4/3)x – 5
D
y= (4/3)x + 5
2
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The y-intercept is and the slope of the line is .

A
–5
B
–4/3
C
4/3
D
5
3

The y-intercept is and the slope of the line is .

A
–5
B
–4/3
C
4/3
D
5
4

Line is the graph of the line –3y = 15 – 4x.

A
A
B
B
C
C
D
D

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