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Transformations of Quadratic Functions

Question 2 • FL-1200330-Algebra 2 CR

Solve for x in the second equation and substitute it into the first equation. The result is .

Answer
A
2(x – 2y – 3) + 5y = –6
B
2(x – 2y) + 5y = –9
C
2(–3 + 2y) + 5y = –6
D
2(–3 – 2y) + 5y = –6

Explanation

The second equation gives x = –3 + 2y. Substituting that expression for x into the first equation, 2x + 5y = –6, gives 2(–3 + 2y) + 5y = –6. This is choice C.

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