On a cold day, the speed of sound in air is 330 m/s. A note with a frequency of 1,320 Hz is played on an instrument. What is the wavelength of that sound wave?

Use the wave equation v = fλ, so the wavelength is λ = v/f. Substituting the given values gives 330 m/s ÷ 1,320 Hz = 0.25 m. Therefore, the wavelength is 0.25 m, choice A.

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