6
QuizMultiple Choice

Work and Power

Question 6 • GA-GSE Physical Science B

A lawnmower engine running for 20 min does 4,560,000 J of work. What is the power output of the engine? (Power: P = W/t)

Answer
A
3800 W
B
228,000 W
C
91,200,000 W
D
547,200,000 W

Explanation

Power is work divided by time: P = W/t. Convert 20 minutes to 1,200 seconds, then calculate 4,560,000 J ÷ 1,200 s = 3,800 W. The engine’s power output is 3,800 W, choice A.

AI-written and checked against the verified answer.

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