Awanita is placing items on a shelf that is 200 cm above the ground. She exerts a force of 20 N to lift a box from the floor to the shelf. She does this in 5 s.What is Awanita’s power output? (Power: P = W/t)

The shelf is 200 cm above the floor, which is 2 m. The work done lifting the box is force × distance = 20 N × 2 m = 40 J. Using P = W/t, the power is 40 J ÷ 5 s = 8 W, so the correct choice is B, 8 W.

AI-written and checked against the verified answer.