What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?

Because the polynomial has real coefficients and i is a root, its conjugate −i must also be a root. The lowest-degree monic polynomial therefore has roots i, −i, −2, and 2, so it is (x − i)(x + i)(x + 2)(x − 2) = (x² + 1)(x² − 4) = x⁴ − 3x² − 4. This matches choice B.

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