AnswersINMT3 Integrated Math 3 Sem 1 26-27The Fundamental Theorem of Algebra

Writing Polynomial Functions from Complex Roots Answers

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To solve for the leading coefficient, use a = –5(0 – 2)(0 – 3)(0 – 5) a = 5(0 – 2)(0 – 3)(0 – 5) 5 = a(0 – 2)(0 – 3)(0 – 5)✔ –5 = a(0 – 2)(0 – 3)(0 – 5).

A
a = –5(0 – 2)(0 – 3)(0 – 5)
B
a = 5(0 – 2)(0 – 3)(0 – 5)
C
5 = a(0 – 2)(0 – 3)(0 – 5)
D
–5 = a(0 – 2)(0 – 3)(0 – 5)
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The linear factors of the cubic are ✔ (x – 2)(x – 3)(x – 5)(x – 2)(x – 3)(x – 5)(x + 5)(x + 2)(x + 3)(x + 5)(x + 2)(x + 3)(x – 5).

A
(x – 2)(x – 3)(x – 5)
B
(x – 2)(x – 3)(x – 5)(x + 5)
C
(x + 2)(x + 3)(x + 5)
D
(x + 2)(x + 3)(x – 5)
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Expand: f(x) = x3 − x2 + x −

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10

The equation of the polynomial function is:

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11

The equation of the polynomial function is:

A
f(x) = (x + (2 + i))(x + (2 – i))(x + 5)
B
f(x) = (x – (2 + i))(x – (2 – i))(x – 5)
C
f(x) = (x – (2 + i))(x – (2 – i))
D
f(x) = (x + (2 + i))(x – (2 – i))(x – 5)
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