An airplane is heading due north at 700 kph, and a wind blows at 60 kph in the direction cap s 45 degrees cap e What is the plane’s ground speed?

The wind blows southeast, so its north–south component opposes the plane’s northward motion. That component is 60 cos 45° ≈ 42.43 kph, leaving a northward component of 700 − 42.43 = 657.57 kph; the wind’s eastward component is also about 42.43 kph. The ground speed is √(657.57² + 42.43²) ≈ 658.94 kph, so the answer is 658.94 kph.

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