Question 4 • Precalculus
The direction S 45° E means 45° east of south, so the velocity has a positive east component and a negative north–south component. Since the angle is 45°, both component magnitudes are 300 cos 45° = 300(√2/2) = 150√2. Thus the component form is ⟨150√2, −150√2⟩, choice C.
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